Triangle Question
Diagram 6 shows a pyramid with its triangle base placed on a horizontal plane. Vertex V. is vertically above P. Given that \angle P Q R=40^{\circ}, P Q=12 \mathrm{~cm}, Q R=10 \mathrm{~cm} and \angle V Q P=50^{\circ}Rajah 6 memunjukkan sebuah pyramid dengan tapak segitiga yang diletakkan atas satah mengufuk. Puncak V berada tegak di atas P. Diberi \angle P Q R=40^{\circ}, P Q=12 \mathrm{~cm}, Q R=10 \mathrm{cm} dan \angle V Q P=50^{\circ}.
Calculate
Hitungkan(a) the length of P R [2 marks]
panjang P R(b) \angle V R P, [2 marks]
(c) the angle between the planes V Q P and V R P. [2 marks]
sudut di antara satah VQP dan VRP.(d) the area of the triangle V Q R. [4marks]
Luas segitiga VQR.
Triangle Solution
Hi,this is my answer for question (a)
Answer B
I’m not sure my answer is correct or not. Please let me know if my answer is wrong.
ANSWER : 61.53° / 61° 32’
Answer C
ANSWER: 180°
Answer D
