## Question

(b)

Bumi bergerak dengan tempoh 3.15 \times 10^7 s pada jarak purata 1.50 \times 10^{11} m dari Matahari.

The Earth moves with a period of 3.15 \times 10^7 s at an average distance of 1.50 \times 10^{11} m from the Sun.

(i) Hitung tempoh Musytari mengelilingi Matahari pada jarak purata 7.79 \times 10^{11} m dari Matahari.

Calculate the period of Jupiter orbiting the Sun at an average distance of 7.79 \times 10^{11} m from the Sun.

### Answer

Hi Farhaini,

For this question, we would use Kepler’s third law to solve.

You probably already know this, the derivation comes from equating centripetal force with gravitational force.

Hope this helps!

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